On Mon, 08 Jul 2013, Paul_Koning@Dell.com wrote:
Perhaps this will work without either a compiler warning or potential loss of precision:
seconds = tdays * SECSPERDAY + (time_t)0.5;
--apb (Alan Barrett)
I rather doubt it. Casting 0.5 to an integer type (as time_t is) ends up adding 0 or 1, but not 0.5.
The whole point of adding 0.5 before converting from time_t to int_fast32_t is to round up if time_t happens to be a floating point type, and to do nothing if time_t happens to be an integral type. You can't assume that time_t is an integral type.
How about (tdays * SECSPERDAY * 2 + 1) / 2; ?
Multiplying by 2 might overflow the available range. (I have not checked whether there are reasons why it would always be safe.) --apb (Alan Barrett)